9x2=47

Solution for 9x2=47 equation:

9x^2=47

We move all terms to the left:

9x^2-(47)=0

a = 9; b = 0; c = -47;
Δ = b2-4ac
Δ = 02-4·9·(-47)
Δ = 1692
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1692}=\sqrt{36*47}=\sqrt{36}*\sqrt{47}=6\sqrt{47}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{47}}{2*9}=\frac{0-6\sqrt{47}}{18}
=-\frac{6\sqrt{47}}{18}
=-\frac{\sqrt{47}}{3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{47}}{2*9}=\frac{0+6\sqrt{47}}{18}
=\frac{6\sqrt{47}}{18}
=\frac{\sqrt{47}}{3}
$