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9x^2-50x+25=0
a = 9; b = -50; c = +25;
Δ = b2-4ac
Δ = -502-4·9·25
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1600}=40$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-40}{2*9}=\frac{10}{18} =5/9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+40}{2*9}=\frac{90}{18} =5 $
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