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9x^2-27x-162=0
a = 9; b = -27; c = -162;
Δ = b2-4ac
Δ = -272-4·9·(-162)
Δ = 6561
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6561}=81$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-81}{2*9}=\frac{-54}{18} =-3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+81}{2*9}=\frac{108}{18} =6 $
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