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9x^2-17x=10x-8
We move all terms to the left:
9x^2-17x-(10x-8)=0
We get rid of parentheses
9x^2-17x-10x+8=0
We add all the numbers together, and all the variables
9x^2-27x+8=0
a = 9; b = -27; c = +8;
Δ = b2-4ac
Δ = -272-4·9·8
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{441}=21$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-21}{2*9}=\frac{6}{18} =1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+21}{2*9}=\frac{48}{18} =2+2/3 $
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