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9x^2+6x-255=0
a = 9; b = 6; c = -255;
Δ = b2-4ac
Δ = 62-4·9·(-255)
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9216}=96$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-96}{2*9}=\frac{-102}{18} =-5+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+96}{2*9}=\frac{90}{18} =5 $
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