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9x^2+5x-126=0
a = 9; b = 5; c = -126;
Δ = b2-4ac
Δ = 52-4·9·(-126)
Δ = 4561
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{4561}}{2*9}=\frac{-5-\sqrt{4561}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{4561}}{2*9}=\frac{-5+\sqrt{4561}}{18} $
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