9x2+3x-7x-21=-9x2-4x-21=0

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Solution for 9x2+3x-7x-21=-9x2-4x-21=0 equation:



9x^2+3x-7x-21=-9x^2-4x-21=0
We move all terms to the left:
9x^2+3x-7x-21-(-9x^2-4x-21)=0
We add all the numbers together, and all the variables
9x^2-(-9x^2-4x-21)-4x-21=0
We get rid of parentheses
9x^2+9x^2+4x-4x+21-21=0
We add all the numbers together, and all the variables
18x^2=0
a = 18; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·18·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{36}=0$

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