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9x^2+13x-8=0
a = 9; b = 13; c = -8;
Δ = b2-4ac
Δ = 132-4·9·(-8)
Δ = 457
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{457}}{2*9}=\frac{-13-\sqrt{457}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{457}}{2*9}=\frac{-13+\sqrt{457}}{18} $
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