9x/10(3-10)=11x+8

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Solution for 9x/10(3-10)=11x+8 equation: 



9x/10(3-10)=11x+8

We move all terms to the left:

9x/10(3-10)-(11x+8)=0

We add all the numbers together, and all the variables

9x/10(-7)-(11x+8)=0

We get rid of parentheses

9x/10(-7)-11x-8=0

We multiply all the terms by the denominator


9x-11x*10(-7)-8*10(-7)=0

We add all the numbers together, and all the variables

9x-11x*10(-7)+560=0

Wy multiply elements

-110x^2(-+560+9x=0

We use the square of the difference formula

-110x^2(-560+9x=0

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