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9x-6x+3=3(x+1)
We move all terms to the left:
9x-6x+3-(3(x+1))=0
We add all the numbers together, and all the variables
3x-(3(x+1))+3=0
We calculate terms in parentheses: -(3(x+1)), so:We get rid of parentheses
3(x+1)
We multiply parentheses
3x+3
Back to the equation:
-(3x+3)
3x-3x-3+3=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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