9x-5(x-8)=2(x-1)+5

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Solution for 9x-5(x-8)=2(x-1)+5 equation: 



9x-5(x-8)=2(x-1)+5

We move all terms to the left:

9x-5(x-8)-(2(x-1)+5)=0

We multiply parentheses

9x-5x-(2(x-1)+5)+40=0



We calculate terms in parentheses: -(2(x-1)+5), so:

2(x-1)+5

We multiply parentheses

2x-2+5

We add all the numbers together, and all the variables

2x+3

Back to the equation:

-(2x+3)



We add all the numbers together, and all the variables

4x-(2x+3)+40=0

We get rid of parentheses

4x-2x-3+40=0

We add all the numbers together, and all the variables

2x+37=0

We move all terms containing x to the left, all other terms to the right

2x=-37

x=-37/2

x=-18+1/2

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