9x-5(x+1)=4(x-3)+7

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Solution for 9x-5(x+1)=4(x-3)+7 equation: 



9x-5(x+1)=4(x-3)+7

We move all terms to the left:

9x-5(x+1)-(4(x-3)+7)=0

We multiply parentheses

9x-5x-(4(x-3)+7)-5=0



We calculate terms in parentheses: -(4(x-3)+7), so:

4(x-3)+7

We multiply parentheses

4x-12+7

We add all the numbers together, and all the variables

4x-5

Back to the equation:

-(4x-5)



We add all the numbers together, and all the variables

4x-(4x-5)-5=0

We get rid of parentheses

4x-4x+5-5=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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