9x-5(3x+4)=14+2(x-1)

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Solution for 9x-5(3x+4)=14+2(x-1) equation: 



9x-5(3x+4)=14+2(x-1)

We move all terms to the left:

9x-5(3x+4)-(14+2(x-1))=0

We multiply parentheses

9x-15x-(14+2(x-1))-20=0



We calculate terms in parentheses: -(14+2(x-1)), so:

14+2(x-1)

determiningTheFunctionDomain
2(x-1)+14

We multiply parentheses

2x-2+14

We add all the numbers together, and all the variables

2x+12

Back to the equation:

-(2x+12)



We add all the numbers together, and all the variables

-6x-(2x+12)-20=0

We get rid of parentheses

-6x-2x-12-20=0

We add all the numbers together, and all the variables

-8x-32=0

We move all terms containing x to the left, all other terms to the right

-8x=32

x=32/-8

x=-4

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