9x-4(4x-8)=3(-8x-1)

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Solution for 9x-4(4x-8)=3(-8x-1) equation: 



9x-4(4x-8)=3(-8x-1)

We move all terms to the left:

9x-4(4x-8)-(3(-8x-1))=0

We multiply parentheses

9x-16x-(3(-8x-1))+32=0



We calculate terms in parentheses: -(3(-8x-1)), so:

3(-8x-1)

We multiply parentheses

-24x-3

Back to the equation:

-(-24x-3)



We add all the numbers together, and all the variables

-7x-(-24x-3)+32=0

We get rid of parentheses

-7x+24x+3+32=0

We add all the numbers together, and all the variables

17x+35=0

We move all terms containing x to the left, all other terms to the right

17x=-35

x=-35/17

x=-2+1/17

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