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9x-4(2x-5)=10+2(3x-25)
We move all terms to the left:
9x-4(2x-5)-(10+2(3x-25))=0
We multiply parentheses
9x-8x-(10+2(3x-25))+20=0
We calculate terms in parentheses: -(10+2(3x-25)), so:We add all the numbers together, and all the variables
10+2(3x-25)
determiningTheFunctionDomain 2(3x-25)+10
We multiply parentheses
6x-50+10
We add all the numbers together, and all the variables
6x-40
Back to the equation:
-(6x-40)
x-(6x-40)+20=0
We get rid of parentheses
x-6x+40+20=0
We add all the numbers together, and all the variables
-5x+60=0
We move all terms containing x to the left, all other terms to the right
-5x=-60
x=-60/-5
x=+12
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