9x-3+3x=6x+77-4x

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Solution for 9x-3+3x=6x+77-4x equation: 



9x-3+3x=6x+77-4x

We move all terms to the left:

9x-3+3x-(6x+77-4x)=0

We add all the numbers together, and all the variables

9x+3x-(2x+77)-3=0

We add all the numbers together, and all the variables

12x-(2x+77)-3=0

We get rid of parentheses

12x-2x-77-3=0

We add all the numbers together, and all the variables

10x-80=0

We move all terms containing x to the left, all other terms to the right

10x=80

x=80/10

x=8

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