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9x-3(2x+4)=2(x-5)
We move all terms to the left:
9x-3(2x+4)-(2(x-5))=0
We multiply parentheses
9x-6x-(2(x-5))-12=0
We calculate terms in parentheses: -(2(x-5)), so:We add all the numbers together, and all the variables
2(x-5)
We multiply parentheses
2x-10
Back to the equation:
-(2x-10)
3x-(2x-10)-12=0
We get rid of parentheses
3x-2x+10-12=0
We add all the numbers together, and all the variables
x-2=0
We move all terms containing x to the left, all other terms to the right
x=2
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