9x-27-3x+12=3(x+2)

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Solution for 9x-27-3x+12=3(x+2) equation: 



9x-27-3x+12=3(x+2)

We move all terms to the left:

9x-27-3x+12-(3(x+2))=0

We add all the numbers together, and all the variables

6x-(3(x+2))-15=0



We calculate terms in parentheses: -(3(x+2)), so:

3(x+2)

We multiply parentheses

3x+6

Back to the equation:

-(3x+6)



We get rid of parentheses

6x-3x-6-15=0

We add all the numbers together, and all the variables

3x-21=0

We move all terms containing x to the left, all other terms to the right

3x=21

x=21/3

x=7

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