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9x-2(x+2)=2(x+3)
We move all terms to the left:
9x-2(x+2)-(2(x+3))=0
We multiply parentheses
9x-2x-(2(x+3))-4=0
We calculate terms in parentheses: -(2(x+3)), so:We add all the numbers together, and all the variables
2(x+3)
We multiply parentheses
2x+6
Back to the equation:
-(2x+6)
7x-(2x+6)-4=0
We get rid of parentheses
7x-2x-6-4=0
We add all the numbers together, and all the variables
5x-10=0
We move all terms containing x to the left, all other terms to the right
5x=10
x=10/5
x=2
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