9x-10=2x(3x+7)

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Solution for 9x-10=2x(3x+7) equation: 



9x-10=2x(3x+7)

We move all terms to the left:

9x-10-(2x(3x+7))=0



We calculate terms in parentheses: -(2x(3x+7)), so:

2x(3x+7)

We multiply parentheses

6x^2+14x

Back to the equation:

-(6x^2+14x)



We get rid of parentheses

-6x^2+9x-14x-10=0

We add all the numbers together, and all the variables

-6x^2-5x-10=0

a = -6; b = -5; c = -10;
Δ = b2-4ac
Δ = -52-4·(-6)·(-10)
Δ = -215
Delta is less than zero, so there is no solution for the equation

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