9x+5=4(x+2+)5x

Solution for 9x+5=4(x+2+)5x equation:

9x+5=4(x+2+)5x

We move all terms to the left:

9x+5-(4(x+2+)5x)=0

We add all the numbers together, and all the variables

9x-(4(+x)5x)+5=0


We calculate terms in parentheses: -(4(+x)5x), so:

4(+x)5x

We multiply parentheses

20x^2

Back to the equation:

-(20x^2)


determiningTheFunctionDomain
-20x^2+9x+5=0

a = -20; b = 9; c = +5;
Δ = b2-4ac
Δ = 92-4·(-20)·5
Δ = 481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{481}}{2*-20}=\frac{-9-\sqrt{481}}{-40}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{481}}{2*-20}=\frac{-9+\sqrt{481}}{-40}
$