9x+3x-10=3x(3x+3)

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Solution for 9x+3x-10=3x(3x+3) equation: 



9x+3x-10=3x(3x+3)

We move all terms to the left:

9x+3x-10-(3x(3x+3))=0

We add all the numbers together, and all the variables

12x-(3x(3x+3))-10=0



We calculate terms in parentheses: -(3x(3x+3)), so:

3x(3x+3)

We multiply parentheses

9x^2+9x

Back to the equation:

-(9x^2+9x)



We get rid of parentheses

-9x^2+12x-9x-10=0

We add all the numbers together, and all the variables

-9x^2+3x-10=0

a = -9; b = 3; c = -10;
Δ = b2-4ac
Δ = 32-4·(-9)·(-10)
Δ = -351
Delta is less than zero, so there is no solution for the equation

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