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9x+3x-10=3(3x+x)=
We move all terms to the left:
9x+3x-10-(3(3x+x))=0
We add all the numbers together, and all the variables
9x+3x-(3(+4x))-10=0
We add all the numbers together, and all the variables
12x-(3(+4x))-10=0
We calculate terms in parentheses: -(3(+4x)), so:We add all the numbers together, and all the variables
3(+4x)
We multiply parentheses
12x
Back to the equation:
-(12x)
-10!=0
There is no solution for this equation
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