9x+2=8x2+6x

Solution for 9x+2=8x2+6x equation:

9x+2=8x^2+6x

We move all terms to the left:

9x+2-(8x^2+6x)=0

We get rid of parentheses

-8x^2+9x-6x+2=0

We add all the numbers together, and all the variables

-8x^2+3x+2=0

a = -8; b = 3; c = +2;
Δ = b2-4ac
Δ = 32-4·(-8)·2
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{73}}{2*-8}=\frac{-3-\sqrt{73}}{-16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{73}}{2*-8}=\frac{-3+\sqrt{73}}{-16}
$