9x+2(x-7)=7(x+1)+5

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Solution for 9x+2(x-7)=7(x+1)+5 equation: 



9x+2(x-7)=7(x+1)+5

We move all terms to the left:

9x+2(x-7)-(7(x+1)+5)=0

We multiply parentheses

9x+2x-(7(x+1)+5)-14=0



We calculate terms in parentheses: -(7(x+1)+5), so:

7(x+1)+5

We multiply parentheses

7x+7+5

We add all the numbers together, and all the variables

7x+12

Back to the equation:

-(7x+12)



We add all the numbers together, and all the variables

11x-(7x+12)-14=0

We get rid of parentheses

11x-7x-12-14=0

We add all the numbers together, and all the variables

4x-26=0

We move all terms containing x to the left, all other terms to the right

4x=26

x=26/4

x=6+1/2

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