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9x+19-7x=5(x+2)
We move all terms to the left:
9x+19-7x-(5(x+2))=0
We add all the numbers together, and all the variables
2x-(5(x+2))+19=0
We calculate terms in parentheses: -(5(x+2)), so:We get rid of parentheses
5(x+2)
We multiply parentheses
5x+10
Back to the equation:
-(5x+10)
2x-5x-10+19=0
We add all the numbers together, and all the variables
-3x+9=0
We move all terms containing x to the left, all other terms to the right
-3x=-9
x=-9/-3
x=+3
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