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9x*7x=80
We move all terms to the left:
9x*7x-(80)=0
Wy multiply elements
63x^2-80=0
a = 63; b = 0; c = -80;
Δ = b2-4ac
Δ = 02-4·63·(-80)
Δ = 20160
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{20160}=\sqrt{576*35}=\sqrt{576}*\sqrt{35}=24\sqrt{35}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24\sqrt{35}}{2*63}=\frac{0-24\sqrt{35}}{126} =-\frac{24\sqrt{35}}{126} =-\frac{4\sqrt{35}}{21} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24\sqrt{35}}{2*63}=\frac{0+24\sqrt{35}}{126} =\frac{24\sqrt{35}}{126} =\frac{4\sqrt{35}}{21} $
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