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9x*7x=2500
We move all terms to the left:
9x*7x-(2500)=0
Wy multiply elements
63x^2-2500=0
a = 63; b = 0; c = -2500;
Δ = b2-4ac
Δ = 02-4·63·(-2500)
Δ = 630000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{630000}=\sqrt{90000*7}=\sqrt{90000}*\sqrt{7}=300\sqrt{7}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-300\sqrt{7}}{2*63}=\frac{0-300\sqrt{7}}{126} =-\frac{300\sqrt{7}}{126} =-\frac{50\sqrt{7}}{21} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+300\sqrt{7}}{2*63}=\frac{0+300\sqrt{7}}{126} =\frac{300\sqrt{7}}{126} =\frac{50\sqrt{7}}{21} $
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