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9x(3x-6)=x(5-9x)
We move all terms to the left:
9x(3x-6)-(x(5-9x))=0
We add all the numbers together, and all the variables
9x(3x-6)-(x(-9x+5))=0
We multiply parentheses
27x^2-54x-(x(-9x+5))=0
We calculate terms in parentheses: -(x(-9x+5)), so:We get rid of parentheses
x(-9x+5)
We multiply parentheses
-9x^2+5x
Back to the equation:
-(-9x^2+5x)
27x^2+9x^2-5x-54x=0
We add all the numbers together, and all the variables
36x^2-59x=0
a = 36; b = -59; c = 0;
Δ = b2-4ac
Δ = -592-4·36·0
Δ = 3481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3481}=59$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-59)-59}{2*36}=\frac{0}{72} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-59)+59}{2*36}=\frac{118}{72} =1+23/36 $
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