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9x(10x+4)=180
We move all terms to the left:
9x(10x+4)-(180)=0
We multiply parentheses
90x^2+36x-180=0
a = 90; b = 36; c = -180;
Δ = b2-4ac
Δ = 362-4·90·(-180)
Δ = 66096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{66096}=\sqrt{1296*51}=\sqrt{1296}*\sqrt{51}=36\sqrt{51}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-36\sqrt{51}}{2*90}=\frac{-36-36\sqrt{51}}{180} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+36\sqrt{51}}{2*90}=\frac{-36+36\sqrt{51}}{180} $
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