9v+32=4(v+3)

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Solution for 9v+32=4(v+3) equation: 



9v+32=4(v+3)

We move all terms to the left:

9v+32-(4(v+3))=0



We calculate terms in parentheses: -(4(v+3)), so:

4(v+3)

We multiply parentheses

4v+12

Back to the equation:

-(4v+12)



We get rid of parentheses

9v-4v-12+32=0

We add all the numbers together, and all the variables

5v+20=0

We move all terms containing v to the left, all other terms to the right

5v=-20

v=-20/5

v=-4

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