9u+35=5(u+3)

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Solution for 9u+35=5(u+3) equation: 



9u+35=5(u+3)

We move all terms to the left:

9u+35-(5(u+3))=0



We calculate terms in parentheses: -(5(u+3)), so:

5(u+3)

We multiply parentheses

5u+15

Back to the equation:

-(5u+15)



We get rid of parentheses

9u-5u-15+35=0

We add all the numbers together, and all the variables

4u+20=0

We move all terms containing u to the left, all other terms to the right

4u=-20

u=-20/4

u=-5

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