9u+3-3(-3u-3)=6(u-1)

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Solution for 9u+3-3(-3u-3)=6(u-1) equation: 



9u+3-3(-3u-3)=6(u-1)

We move all terms to the left:

9u+3-3(-3u-3)-(6(u-1))=0

We multiply parentheses

9u+9u-(6(u-1))+9+3=0



We calculate terms in parentheses: -(6(u-1)), so:

6(u-1)

We multiply parentheses

6u-6

Back to the equation:

-(6u-6)



We add all the numbers together, and all the variables

18u-(6u-6)+12=0

We get rid of parentheses

18u-6u+6+12=0

We add all the numbers together, and all the variables

12u+18=0

We move all terms containing u to the left, all other terms to the right

12u=-18

u=-18/12

u=-1+1/2

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