9t2/3t=12

Solution for 9t2/3t=12 equation:

9t^2/3t=12

We move all terms to the left:

9t^2/3t-(12)=0


Domain of the equation: 3t!=0

t!=0/3

t!=0

t∈R


We multiply all the terms by the denominator


9t^2-12*3t=0

Wy multiply elements

9t^2-36t=0

a = 9; b = -36; c = 0;
Δ = b2-4ac
Δ = -362-4·9·0
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-36}{2*9}=\frac{0}{18}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+36}{2*9}=\frac{72}{18}
=4
$