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9t^2-81=0
a = 9; b = 0; c = -81;
Δ = b2-4ac
Δ = 02-4·9·(-81)
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2916}=54$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-54}{2*9}=\frac{-54}{18} =-3 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+54}{2*9}=\frac{54}{18} =3 $
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