9r-3(r+4)=3(4r-6)-12

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Solution for 9r-3(r+4)=3(4r-6)-12 equation: 



9r-3(r+4)=3(4r-6)-12

We move all terms to the left:

9r-3(r+4)-(3(4r-6)-12)=0

We multiply parentheses

9r-3r-(3(4r-6)-12)-12=0



We calculate terms in parentheses: -(3(4r-6)-12), so:

3(4r-6)-12

We multiply parentheses

12r-18-12

We add all the numbers together, and all the variables

12r-30

Back to the equation:

-(12r-30)



We add all the numbers together, and all the variables

6r-(12r-30)-12=0

We get rid of parentheses

6r-12r+30-12=0

We add all the numbers together, and all the variables

-6r+18=0

We move all terms containing r to the left, all other terms to the right

-6r=-18

r=-18/-6

r=+3

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