9r-2(r+2)=5(4r-5)-31

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Solution for 9r-2(r+2)=5(4r-5)-31 equation: 



9r-2(r+2)=5(4r-5)-31

We move all terms to the left:

9r-2(r+2)-(5(4r-5)-31)=0

We multiply parentheses

9r-2r-(5(4r-5)-31)-4=0



We calculate terms in parentheses: -(5(4r-5)-31), so:

5(4r-5)-31

We multiply parentheses

20r-25-31

We add all the numbers together, and all the variables

20r-56

Back to the equation:

-(20r-56)



We add all the numbers together, and all the variables

7r-(20r-56)-4=0

We get rid of parentheses

7r-20r+56-4=0

We add all the numbers together, and all the variables

-13r+52=0

We move all terms containing r to the left, all other terms to the right

-13r=-52

r=-52/-13

r=+4

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