9n2-23n+20=3n2

Solution for 9n2-23n+20=3n2 equation:

9n^2-23n+20=3n^2

We move all terms to the left:

9n^2-23n+20-(3n^2)=0

determiningTheFunctionDomain
9n^2-3n^2-23n+20=0

We add all the numbers together, and all the variables

6n^2-23n+20=0

a = 6; b = -23; c = +20;
Δ = b2-4ac
Δ = -232-4·6·20
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-23)-7}{2*6}=\frac{16}{12}
=1+1/3
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-23)+7}{2*6}=\frac{30}{12}
=2+1/2
$