9n+48=72-2(n-2)

Solution for 9n+48=72-2(n-2) equation:

9n+48=72-2(n-2)

We move all terms to the left:

9n+48-(72-2(n-2))=0


We calculate terms in parentheses: -(72-2(n-2)), so:

72-2(n-2)

determiningTheFunctionDomain
-2(n-2)+72

We multiply parentheses

-2n+4+72

We add all the numbers together, and all the variables

-2n+76

Back to the equation:

-(-2n+76)


We get rid of parentheses

9n+2n-76+48=0

We add all the numbers together, and all the variables

11n-28=0

We move all terms containing n to the left, all other terms to the right

11n=28

n=28/11

n=2+6/11