9n+3(n-3)=4(4n-9)+5n

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Solution for 9n+3(n-3)=4(4n-9)+5n equation: 



9n+3(n-3)=4(4n-9)+5n

We move all terms to the left:

9n+3(n-3)-(4(4n-9)+5n)=0

We multiply parentheses

9n+3n-(4(4n-9)+5n)-9=0



We calculate terms in parentheses: -(4(4n-9)+5n), so:

4(4n-9)+5n

We add all the numbers together, and all the variables

5n+4(4n-9)

We multiply parentheses

5n+16n-36

We add all the numbers together, and all the variables

21n-36

Back to the equation:

-(21n-36)



We add all the numbers together, and all the variables

12n-(21n-36)-9=0

We get rid of parentheses

12n-21n+36-9=0

We add all the numbers together, and all the variables

-9n+27=0

We move all terms containing n to the left, all other terms to the right

-9n=-27

n=-27/-9

n=+3

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