9k-4(k+8)=3(2k-7)

Solution for 9k-4(k+8)=3(2k-7) equation:

9k-4(k+8)=3(2k-7)

We move all terms to the left:

9k-4(k+8)-(3(2k-7))=0

We multiply parentheses

9k-4k-(3(2k-7))-32=0


We calculate terms in parentheses: -(3(2k-7)), so:

3(2k-7)

We multiply parentheses

6k-21

Back to the equation:

-(6k-21)


We add all the numbers together, and all the variables

5k-(6k-21)-32=0

We get rid of parentheses

5k-6k+21-32=0

We add all the numbers together, and all the variables

-1k-11=0

We move all terms containing k to the left, all other terms to the right

-k=11

k=11/-1

k=-11