9k^2=27k

Solution for 9k^2=27k equation:

9k^2=27k

We move all terms to the left:

9k^2-(27k)=0

a = 9; b = -27; c = 0;
Δ = b2-4ac
Δ = -272-4·9·0
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{729}=27$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-27}{2*9}=\frac{0}{18}
=0
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+27}{2*9}=\frac{54}{18}
=3
$