9i-10+22=3(i+7)

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Solution for 9i-10+22=3(i+7) equation: 



9i-10+22=3(i+7)

We move all terms to the left:

9i-10+22-(3(i+7))=0

We add all the numbers together, and all the variables

9i-(3(i+7))+12=0



We calculate terms in parentheses: -(3(i+7)), so:

3(i+7)

We multiply parentheses

3i+21

Back to the equation:

-(3i+21)



We get rid of parentheses

9i-3i-21+12=0

We add all the numbers together, and all the variables

6i-9=0

We move all terms containing i to the left, all other terms to the right

6i=9

i=9/6

i=1+1/2

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