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9g^2+32g=0
a = 9; b = 32; c = 0;
Δ = b2-4ac
Δ = 322-4·9·0
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1024}=32$$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-32}{2*9}=\frac{-64}{18} =-3+5/9 $$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+32}{2*9}=\frac{0}{18} =0 $
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