9f=3(2-f)-18

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Solution for 9f=3(2-f)-18 equation: 



9f=3(2-f)-18

We move all terms to the left:

9f-(3(2-f)-18)=0

We add all the numbers together, and all the variables

9f-(3(-1f+2)-18)=0



We calculate terms in parentheses: -(3(-1f+2)-18), so:

3(-1f+2)-18

We multiply parentheses

-3f+6-18

We add all the numbers together, and all the variables

-3f-12

Back to the equation:

-(-3f-12)



We get rid of parentheses

9f+3f+12=0

We add all the numbers together, and all the variables

12f+12=0

We move all terms containing f to the left, all other terms to the right

12f=-12

f=-12/12

f=-1

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