9c+6=3(c-10)

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Solution for 9c+6=3(c-10) equation: 



9c+6=3(c-10)

We move all terms to the left:

9c+6-(3(c-10))=0



We calculate terms in parentheses: -(3(c-10)), so:

3(c-10)

We multiply parentheses

3c-30

Back to the equation:

-(3c-30)



We get rid of parentheses

9c-3c+30+6=0

We add all the numbers together, and all the variables

6c+36=0

We move all terms containing c to the left, all other terms to the right

6c=-36

c=-36/6

c=-6

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