9b-4-6b=2(b+1)-5

Solution for 9b-4-6b=2(b+1)-5 equation:

9b-4-6b=2(b+1)-5

We move all terms to the left:

9b-4-6b-(2(b+1)-5)=0

We add all the numbers together, and all the variables

3b-(2(b+1)-5)-4=0


We calculate terms in parentheses: -(2(b+1)-5), so:

2(b+1)-5

We multiply parentheses

2b+2-5

We add all the numbers together, and all the variables

2b-3

Back to the equation:

-(2b-3)


We get rid of parentheses

3b-2b+3-4=0

We add all the numbers together, and all the variables

b-1=0

We move all terms containing b to the left, all other terms to the right

b=1