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9b^2+27b+8=0
a = 9; b = 27; c = +8;
Δ = b2-4ac
Δ = 272-4·9·8
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{441}=21$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-21}{2*9}=\frac{-48}{18} =-2+2/3 $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+21}{2*9}=\frac{-6}{18} =-1/3 $
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