9a=5(3-a)=11

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Solution for 9a=5(3-a)=11 equation: 



9a=5(3-a)=11

We move all terms to the left:

9a-(5(3-a))=0

We add all the numbers together, and all the variables

9a-(5(-1a+3))=0



We calculate terms in parentheses: -(5(-1a+3)), so:

5(-1a+3)

We multiply parentheses

-5a+15

Back to the equation:

-(-5a+15)



We get rid of parentheses

9a+5a-15=0

We add all the numbers together, and all the variables

14a-15=0

We move all terms containing a to the left, all other terms to the right

14a=15

a=15/14

a=1+1/14

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