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9a-6=3-6/4a
We move all terms to the left:
9a-6-(3-6/4a)=0
Domain of the equation: 4a)!=0We add all the numbers together, and all the variables
a!=0/1
a!=0
a∈R
9a-(-6/4a+3)-6=0
We get rid of parentheses
9a+6/4a-3-6=0
We multiply all the terms by the denominator
9a*4a-3*4a-6*4a+6=0
Wy multiply elements
36a^2-12a-24a+6=0
We add all the numbers together, and all the variables
36a^2-36a+6=0
a = 36; b = -36; c = +6;
Δ = b2-4ac
Δ = -362-4·36·6
Δ = 432
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{432}=\sqrt{144*3}=\sqrt{144}*\sqrt{3}=12\sqrt{3}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-12\sqrt{3}}{2*36}=\frac{36-12\sqrt{3}}{72} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+12\sqrt{3}}{2*36}=\frac{36+12\sqrt{3}}{72} $
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